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Post by Sara on Mar 4, 2016 14:14:10 GMT -8
I bought a 2000 watt pure sign inverter and don't know what size of fuse I need leading to it. Thank you for your help!
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Post by spiderbob on Mar 4, 2016 17:10:50 GMT -8
You didn't give much info needed so I'll just say what I did, I have a Xantrex 1800, so as your batteries can provide a multitude of amps of short-circuit current, you need fuses that can interrupt the short -circuit current. What kind of batteries are you using and what system do you have them in?
If you are using one battery to power your inverter and its short-circuit current rating is 500A (check your battery short-circuit current rating) then you have 500A
If you are powering your inverter with two 12v batteries in parallel, and each battery has a short-circuit current orating of 500A, then you have a total of 1000A
If you are powering your inverter with two 6 v batteries, as I do, connected in series, and each battery has a short-circuit current rating of 500 A, the total is 500a
So according to my book based on the product (batteries) used: 250 ADC for my 1800w.
What does your manual say to use for your inverter?
Important to make sure your cable going from inverter to battery is sufficient size. I use welding cable 1/0.
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